[keek] extract uploader and uploader id with _search_regex
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@ -1,8 +1,6 @@
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# coding: utf-8
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# coding: utf-8
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from __future__ import unicode_literals
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from __future__ import unicode_literals
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import re
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from .common import InfoExtractor
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from .common import InfoExtractor
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@ -26,10 +24,6 @@ class KeekIE(InfoExtractor):
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video_id = self._match_id(url)
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video_id = self._match_id(url)
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webpage = self._download_webpage(url, video_id)
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webpage = self._download_webpage(url, video_id)
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uploader = uploader_id = None
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matches = re.search(r'data-username="(?P<uploader>[^"]+)"[^>]*data-user-id="(?P<uploader_id>[^"]+)"', webpage)
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if matches:
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uploader, uploader_id = matches.groups()
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return {
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return {
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'id': video_id,
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'id': video_id,
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@ -38,6 +32,6 @@ class KeekIE(InfoExtractor):
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'title': self._og_search_title(webpage),
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'title': self._og_search_title(webpage),
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'description': self._og_search_description(webpage),
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'description': self._og_search_description(webpage),
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'thumbnail': self._og_search_thumbnail(webpage),
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'thumbnail': self._og_search_thumbnail(webpage),
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'uploader': uploader,
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'uploader': self._search_regex(r'data-username="([^"]+)"', webpage, 'uploader', None),
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'uploader_id': uploader_id,
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'uploader_id': self._search_regex(r'data-user-id="([^"]+)"', webpage, 'uploader id', None),
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}
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}
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